Optimal. Leaf size=74 \[ -\frac{a}{4 x^4}-\frac{1}{4} b d^2 \sin (c) \text{CosIntegral}\left (d x^2\right )-\frac{1}{4} b d^2 \cos (c) \text{Si}\left (d x^2\right )-\frac{b \sin \left (c+d x^2\right )}{4 x^4}-\frac{b d \cos \left (c+d x^2\right )}{4 x^2} \]
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Rubi [A] time = 0.125384, antiderivative size = 74, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 6, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.375, Rules used = {14, 3379, 3297, 3303, 3299, 3302} \[ -\frac{a}{4 x^4}-\frac{1}{4} b d^2 \sin (c) \text{CosIntegral}\left (d x^2\right )-\frac{1}{4} b d^2 \cos (c) \text{Si}\left (d x^2\right )-\frac{b \sin \left (c+d x^2\right )}{4 x^4}-\frac{b d \cos \left (c+d x^2\right )}{4 x^2} \]
Antiderivative was successfully verified.
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Rule 14
Rule 3379
Rule 3297
Rule 3303
Rule 3299
Rule 3302
Rubi steps
\begin{align*} \int \frac{a+b \sin \left (c+d x^2\right )}{x^5} \, dx &=\int \left (\frac{a}{x^5}+\frac{b \sin \left (c+d x^2\right )}{x^5}\right ) \, dx\\ &=-\frac{a}{4 x^4}+b \int \frac{\sin \left (c+d x^2\right )}{x^5} \, dx\\ &=-\frac{a}{4 x^4}+\frac{1}{2} b \operatorname{Subst}\left (\int \frac{\sin (c+d x)}{x^3} \, dx,x,x^2\right )\\ &=-\frac{a}{4 x^4}-\frac{b \sin \left (c+d x^2\right )}{4 x^4}+\frac{1}{4} (b d) \operatorname{Subst}\left (\int \frac{\cos (c+d x)}{x^2} \, dx,x,x^2\right )\\ &=-\frac{a}{4 x^4}-\frac{b d \cos \left (c+d x^2\right )}{4 x^2}-\frac{b \sin \left (c+d x^2\right )}{4 x^4}-\frac{1}{4} \left (b d^2\right ) \operatorname{Subst}\left (\int \frac{\sin (c+d x)}{x} \, dx,x,x^2\right )\\ &=-\frac{a}{4 x^4}-\frac{b d \cos \left (c+d x^2\right )}{4 x^2}-\frac{b \sin \left (c+d x^2\right )}{4 x^4}-\frac{1}{4} \left (b d^2 \cos (c)\right ) \operatorname{Subst}\left (\int \frac{\sin (d x)}{x} \, dx,x,x^2\right )-\frac{1}{4} \left (b d^2 \sin (c)\right ) \operatorname{Subst}\left (\int \frac{\cos (d x)}{x} \, dx,x,x^2\right )\\ &=-\frac{a}{4 x^4}-\frac{b d \cos \left (c+d x^2\right )}{4 x^2}-\frac{1}{4} b d^2 \text{Ci}\left (d x^2\right ) \sin (c)-\frac{b \sin \left (c+d x^2\right )}{4 x^4}-\frac{1}{4} b d^2 \cos (c) \text{Si}\left (d x^2\right )\\ \end{align*}
Mathematica [A] time = 0.0866247, size = 86, normalized size = 1.16 \[ -\frac{a}{4 x^4}-\frac{1}{4} b d^2 \left (\sin (c) \text{CosIntegral}\left (d x^2\right )+\cos (c) \text{Si}\left (d x^2\right )\right )-\frac{b \cos \left (d x^2\right ) \left (d x^2 \cos (c)+\sin (c)\right )}{4 x^4}+\frac{b \sin \left (d x^2\right ) \left (d x^2 \sin (c)-\cos (c)\right )}{4 x^4} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.009, size = 65, normalized size = 0.9 \begin{align*} -{\frac{a}{4\,{x}^{4}}}+b \left ( -{\frac{\sin \left ( d{x}^{2}+c \right ) }{4\,{x}^{4}}}+{\frac{d}{2} \left ( -{\frac{\cos \left ( d{x}^{2}+c \right ) }{2\,{x}^{2}}}-d \left ({\frac{\cos \left ( c \right ){\it Si} \left ( d{x}^{2} \right ) }{2}}+{\frac{\sin \left ( c \right ){\it Ci} \left ( d{x}^{2} \right ) }{2}} \right ) \right ) } \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [C] time = 1.15642, size = 78, normalized size = 1.05 \begin{align*} \frac{1}{4} \,{\left ({\left (i \, \Gamma \left (-2, i \, d x^{2}\right ) - i \, \Gamma \left (-2, -i \, d x^{2}\right )\right )} \cos \left (c\right ) +{\left (\Gamma \left (-2, i \, d x^{2}\right ) + \Gamma \left (-2, -i \, d x^{2}\right )\right )} \sin \left (c\right )\right )} b d^{2} - \frac{a}{4 \, x^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.928, size = 242, normalized size = 3.27 \begin{align*} -\frac{2 \, b d^{2} x^{4} \cos \left (c\right ) \operatorname{Si}\left (d x^{2}\right ) + 2 \, b d x^{2} \cos \left (d x^{2} + c\right ) + 2 \, b \sin \left (d x^{2} + c\right ) +{\left (b d^{2} x^{4} \operatorname{Ci}\left (d x^{2}\right ) + b d^{2} x^{4} \operatorname{Ci}\left (-d x^{2}\right )\right )} \sin \left (c\right ) + 2 \, a}{8 \, x^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{a + b \sin{\left (c + d x^{2} \right )}}{x^{5}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.11717, size = 275, normalized size = 3.72 \begin{align*} -\frac{{\left (d x^{2} + c\right )}^{2} b d^{3} \operatorname{Ci}\left (d x^{2}\right ) \sin \left (c\right ) - 2 \,{\left (d x^{2} + c\right )} b c d^{3} \operatorname{Ci}\left (d x^{2}\right ) \sin \left (c\right ) + b c^{2} d^{3} \operatorname{Ci}\left (d x^{2}\right ) \sin \left (c\right ) +{\left (d x^{2} + c\right )}^{2} b d^{3} \cos \left (c\right ) \operatorname{Si}\left (d x^{2}\right ) - 2 \,{\left (d x^{2} + c\right )} b c d^{3} \cos \left (c\right ) \operatorname{Si}\left (d x^{2}\right ) + b c^{2} d^{3} \cos \left (c\right ) \operatorname{Si}\left (d x^{2}\right ) +{\left (d x^{2} + c\right )} b d^{3} \cos \left (d x^{2} + c\right ) - b c d^{3} \cos \left (d x^{2} + c\right ) + b d^{3} \sin \left (d x^{2} + c\right ) + a d^{3}}{4 \,{\left ({\left (d x^{2} + c\right )}^{2} - 2 \,{\left (d x^{2} + c\right )} c + c^{2}\right )} d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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